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The ratio of dogs to cats at the local shelter is 2 to 5. There are 20 dogs at the shelter. What is the total number of cats and dogs at the shelter? A. 28 B. 50 C. 70 D. 8 Need
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cats at a local shelter is 2-5, so we have dogs two cats, It's 2: five. There are 20 dogs at the shelter. What is the total number of cats and dogs at the shelter? So what I'm going to have to do is two times 10 is 20 So five times 10 is 50. Then I'm going to add 50 plus 20 because that means that there's 20 dogs and 50 cats And that means that it's going to equal 70. So the answer is C 70. So There is a total of 70 dogs and cats at the shelter. This is the middle school math teacher signing out.
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Ruth P. You have to figure out how many cats and dog are at the pound on Wednesday. Would 8 cats and 14 dogs be possible? More
1 Expert Answer
Laurie C. answered • 01/27/15
ACT SAT Algebra Geometry College Apps/Essays Certified Teacher
8 cats and 14 dogs would not work because 8(2.35) + 14(5.50) = 95.80
Since the amount is too high, try increasing the number of cats and decreasing the number of dogs:
9(2.35) + 13(5.50) =
10(2.35) + 12(5.50) =
Did they give you the total number of animals?
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Question:
An animal shelter spends $2.35 per day to care for each cat and $5.50 per day to care for each dog. Pat noticed that the shelter spent $89.50 caring for cats and dogs on Wednesday. Later, Pat found a record showing that there were a total of 22 cats and dogs at the shelter on Wednesday. How many cats were at the shelter on Wednesday?
System of Equations:
When a problem has several unknowns, there is a higher possibility of developing a solution when there is a system of equations. The system should contain the same number of equations as the number of unknowns in order to do so.
Answer and Explanation: 1
Let c and d represent the number of cats and dogs, respectively, that were cared for on Wednesday. One equation from the problem can be made from how much was spent on Wednesday as shown:
$$2.35 c + 5.5d = 89.5 \tag{Eq. 1} $$
Pat also noticed that there were a total of 22 cats and dogs at the shelter which can be expressed as:
$$c + d = 22 \tag{Eq. 2} $$
Since the problem is only asking for the number of cats, use Eq. 2 to make an identity for the number of dogs:
$$d = 22 - c \tag{Eq. 3} $$
Substitute this in Eq. 1 and solve for the number of cats:
$$\begin{align} 2.35 c + 5.5d &= 89.5 \tag{Eq. 1} \\ 2.35 c + 5.5(22 - c) &= 89.5 \\ 2.35 c + 121 -5.5 c &= 89.5 \\ -3.15 c &= 89.5 - 121 \\ \dfrac {-3.15 c}{-3.15} &= \dfrac {-31.5}{-3.15} \\ c &= 10 \end{align} $$
There are {eq}\color{blue}{10 \text{ cats}} {/eq} that were in the shelter on Wednesday.
Learn more about this topic:
Solving Word Problems with Money
from
Chapter 30 / Lesson 2
Learn how to solve word problems with money. Explore strategies for solving money word problems. Review examples for each of the four operations.